func_get_args --
Returns an array comprising a function's argument list
Syntax
array func_get_args ( void )
Returns an array in which each element is a copy of the corresponding
member of the current user-defined function's argument
list. func_get_args() will generate a warning
if called from outside of a function definition.
This function cannot be used directly as a function parameter. Instead,
its result may be assigned to a variable, which can then be passed to
the function.
Note:
This function returns a copy of the passed arguments only, and does not
account for default (non-passed) arguments.
<?php function foo() { $numargs = func_num_args(); echo "Number of arguments: $numargs<br />\n"; if ($numargs >= 2) { echo "Second argument is: " . func_get_arg(1) . "<br />\n"; } $arg_list = func_get_args(); for ($i = 0; $i < $numargs; $i++) { echo "Argument $i is: " . $arg_list[$i] . "<br />\n"; } }
foo(1, 2, 3); ?>
func_get_args() may be used in conjunction
with func_num_args() and
func_get_arg() to allow user-defined functions
to accept variable-length argument lists.
Php func get args Function syntax tag
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Php func get args syntax tutorial
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